Reorder indexOf methods in file

git-svn-id: https://svn.apache.org/repos/asf/jakarta/commons/proper/lang/trunk@137555 13f79535-47bb-0310-9956-ffa450edef68
This commit is contained in:
Stephen Colebourne 2003-08-01 23:58:30 +00:00
parent 8ce98776ee
commit fd27d2ecdf
1 changed files with 102 additions and 102 deletions

View File

@ -144,7 +144,7 @@ import java.util.List;
* @author <a href="mailto:ggregory@seagullsw.com">Gary Gregory</a>
* @author Phil Steitz
* @since 1.0
* @version $Id: StringUtils.java,v 1.90 2003/08/01 23:54:41 scolebourne Exp $
* @version $Id: StringUtils.java,v 1.91 2003/08/01 23:58:30 scolebourne Exp $
*/
public class StringUtils {
// Performance testing notes (JDK 1.4, Jul03, scolebourne)
@ -1011,107 +1011,6 @@ public class StringUtils {
return (str.indexOf(searchStr) >= 0);
}
// IndexOfAny strings
//-----------------------------------------------------------------------
/**
* <p>Find the first index of any of a set of potential substrings.</p>
*
* <p>A <code>null</code> String will return <code>-1</code>.
* A <code>null</code> or zero length search array will return <code>-1</code>.
* A <code>null</code> search array entry will be ignored, but a search
* array containing "" will return <code>0</code> if <code>str</code> is not
* null. This method uses {@link String#indexOf(String)}.</p>
*
* <pre>
* StringUtils.indexOfAny(null, *) = -1
* StringUtils.indexOfAny(*, null) = -1
* StringUtils.indexOfAny(*, []) = -1
* StringUtils.indexOfAny("zzabyycdxx", ["ab","cd"]) = 2
* StringUtils.indexOfAny("zzabyycdxx", ["cd","ab"]) = 2
* StringUtils.indexOfAny("zzabyycdxx", ["mn","op"]) = -1
* StringUtils.indexOfAny("zzabyycdxx", ["zab","aby"]) = 1
* StringUtils.indexOfAny("zzabyycdxx", [""]) = 0
* StringUtils.indexOfAny("", [""]) = 0
* StringUtils.indexOfAny("", ["a"]) = -1
* </pre>
*
* @param str the String to check, may be null
* @param searchStrs the Strings to search for, may be null
* @return the first index of any of the searchStrs in str, -1 if no match
*/
public static int indexOfAny(String str, String[] searchStrs) {
if ((str == null) || (searchStrs == null)) {
return -1;
}
int sz = searchStrs.length;
// String's can't have a MAX_VALUEth index.
int ret = Integer.MAX_VALUE;
int tmp = 0;
for (int i = 0; i < sz; i++) {
String search = searchStrs[i];
if (search == null) {
continue;
}
tmp = str.indexOf(search);
if (tmp == -1) {
continue;
}
if (tmp < ret) {
ret = tmp;
}
}
return (ret == Integer.MAX_VALUE) ? -1 : ret;
}
/**
* <p>Find the latest index of any of a set of potential substrings.</p>
*
* <p>A <code>null</code> String will return <code>-1</code>.
* A <code>null</code> search array will return <code>-1</code>.
* A <code>null</code> or zero length search array entry will be ignored,
* but a search array containing "" will return the length of <code>str</code>
* if <code>str</code> is not null. This method uses {@link String#indexOf(String)}</p>
*
* <pre>
* StringUtils.lastIndexOfAny(null, *) = -1
* StringUtils.lastIndexOfAny(*, null) = -1
* StringUtils.lastIndexOfAny(*, []) = -1
* StringUtils.lastIndexOfAny(*, [null]) = -1
* StringUtils.lastIndexOfAny("zzabyycdxx", ["ab","cd"]) = 6
* StringUtils.lastIndexOfAny("zzabyycdxx", ["cd","ab"]) = 6
* StringUtils.lastIndexOfAny("zzabyycdxx", ["mn","op"]) = -1
* StringUtils.lastIndexOfAny("zzabyycdxx", ["mn","op"]) = -1
* StringUtils.lastIndexOfAny("zzabyycdxx", ["mn",""]) = 10
* </pre>
*
* @param str the String to check, may be null
* @param searchStrs the Strings to search for, may be null
* @return the last index of any of the Strings, -1 if no match
*/
public static int lastIndexOfAny(String str, String[] searchStrs) {
if ((str == null) || (searchStrs == null)) {
return -1;
}
int sz = searchStrs.length;
int ret = -1;
int tmp = 0;
for (int i = 0; i < sz; i++) {
String search = searchStrs[i];
if (search == null) {
continue;
}
tmp = str.lastIndexOf(search);
if (tmp > ret) {
ret = tmp;
}
}
return ret;
}
// IndexOfAny chars
//-----------------------------------------------------------------------
/**
@ -1383,6 +1282,107 @@ public class StringUtils {
return containsNone(str, invalidChars.toCharArray());
}
// IndexOfAny strings
//-----------------------------------------------------------------------
/**
* <p>Find the first index of any of a set of potential substrings.</p>
*
* <p>A <code>null</code> String will return <code>-1</code>.
* A <code>null</code> or zero length search array will return <code>-1</code>.
* A <code>null</code> search array entry will be ignored, but a search
* array containing "" will return <code>0</code> if <code>str</code> is not
* null. This method uses {@link String#indexOf(String)}.</p>
*
* <pre>
* StringUtils.indexOfAny(null, *) = -1
* StringUtils.indexOfAny(*, null) = -1
* StringUtils.indexOfAny(*, []) = -1
* StringUtils.indexOfAny("zzabyycdxx", ["ab","cd"]) = 2
* StringUtils.indexOfAny("zzabyycdxx", ["cd","ab"]) = 2
* StringUtils.indexOfAny("zzabyycdxx", ["mn","op"]) = -1
* StringUtils.indexOfAny("zzabyycdxx", ["zab","aby"]) = 1
* StringUtils.indexOfAny("zzabyycdxx", [""]) = 0
* StringUtils.indexOfAny("", [""]) = 0
* StringUtils.indexOfAny("", ["a"]) = -1
* </pre>
*
* @param str the String to check, may be null
* @param searchStrs the Strings to search for, may be null
* @return the first index of any of the searchStrs in str, -1 if no match
*/
public static int indexOfAny(String str, String[] searchStrs) {
if ((str == null) || (searchStrs == null)) {
return -1;
}
int sz = searchStrs.length;
// String's can't have a MAX_VALUEth index.
int ret = Integer.MAX_VALUE;
int tmp = 0;
for (int i = 0; i < sz; i++) {
String search = searchStrs[i];
if (search == null) {
continue;
}
tmp = str.indexOf(search);
if (tmp == -1) {
continue;
}
if (tmp < ret) {
ret = tmp;
}
}
return (ret == Integer.MAX_VALUE) ? -1 : ret;
}
/**
* <p>Find the latest index of any of a set of potential substrings.</p>
*
* <p>A <code>null</code> String will return <code>-1</code>.
* A <code>null</code> search array will return <code>-1</code>.
* A <code>null</code> or zero length search array entry will be ignored,
* but a search array containing "" will return the length of <code>str</code>
* if <code>str</code> is not null. This method uses {@link String#indexOf(String)}</p>
*
* <pre>
* StringUtils.lastIndexOfAny(null, *) = -1
* StringUtils.lastIndexOfAny(*, null) = -1
* StringUtils.lastIndexOfAny(*, []) = -1
* StringUtils.lastIndexOfAny(*, [null]) = -1
* StringUtils.lastIndexOfAny("zzabyycdxx", ["ab","cd"]) = 6
* StringUtils.lastIndexOfAny("zzabyycdxx", ["cd","ab"]) = 6
* StringUtils.lastIndexOfAny("zzabyycdxx", ["mn","op"]) = -1
* StringUtils.lastIndexOfAny("zzabyycdxx", ["mn","op"]) = -1
* StringUtils.lastIndexOfAny("zzabyycdxx", ["mn",""]) = 10
* </pre>
*
* @param str the String to check, may be null
* @param searchStrs the Strings to search for, may be null
* @return the last index of any of the Strings, -1 if no match
*/
public static int lastIndexOfAny(String str, String[] searchStrs) {
if ((str == null) || (searchStrs == null)) {
return -1;
}
int sz = searchStrs.length;
int ret = -1;
int tmp = 0;
for (int i = 0; i < sz; i++) {
String search = searchStrs[i];
if (search == null) {
continue;
}
tmp = str.lastIndexOf(search);
if (tmp > ret) {
ret = tmp;
}
}
return ret;
}
// Substring
//-----------------------------------------------------------------------
/**