HBASE-6994 minor doc update about DEFAULT_ACCEPTABLE_FACTOR (Liang Xie)
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@ -2262,26 +2262,26 @@ rs.close();
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of time. </para>
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<para>The way to calculate how much memory is available in HBase for caching is: </para>
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<programlisting>
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number of region servers * heap size * hfile.block.cache.size * 0.85
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number of region servers * heap size * hfile.block.cache.size * 0.99
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</programlisting>
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<para>The default value for the block cache is 0.25 which represents 25% of the available
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heap. The last value (85%) is the default acceptable loading factor in the LRU cache
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heap. The last value (99%) is the default acceptable loading factor in the LRU cache
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after which eviction is started. The reason it is included in this equation is that it
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would be unrealistic to say that it is possible to use 100% of the available memory
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since this would make the process blocking from the point where it loads new blocks.
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Here are some examples: </para>
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<itemizedlist>
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<listitem>
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<para>One region server with the default heap size (1GB) and the default block cache
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size will have 217MB of block cache available.</para>
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<para>One region server with the default heap size (1 GB) and the default block cache
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size will have 253 MB of block cache available.</para>
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</listitem>
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<listitem>
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<para>20 region servers with the heap size set to 8GB and a default block cache size
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will have 34GB of block cache.</para>
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<para>20 region servers with the heap size set to 8 GB and a default block cache size
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will have 39.6 of block cache.</para>
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</listitem>
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<listitem>
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<para>100 region servers with the heap size set to 24GB and a block cache size of 0.5
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will have about 1TB of block cache.</para>
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<para>100 region servers with the heap size set to 24 GB and a block cache size of 0.5
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will have about 1.16 TB of block cache.</para>
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</listitem>
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</itemizedlist>
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<para>Your data is not the only resident of the block cache. Here are others that you may have to take into account:
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