From 1b4417fb90b826eee8263548b4d4f08bb8f848d0 Mon Sep 17 00:00:00 2001 From: Otis Gospodnetic Date: Fri, 27 Apr 2007 18:25:11 +0000 Subject: [PATCH] - Javadoc typos git-svn-id: https://svn.apache.org/repos/asf/lucene/solr/trunk@533184 13f79535-47bb-0310-9956-ffa450edef68 --- .../org/apache/solr/analysis/PatternTokenizerFactory.java | 8 ++++---- 1 file changed, 4 insertions(+), 4 deletions(-) diff --git a/src/java/org/apache/solr/analysis/PatternTokenizerFactory.java b/src/java/org/apache/solr/analysis/PatternTokenizerFactory.java index ee9eaaee52b..085fbe95e7f 100644 --- a/src/java/org/apache/solr/analysis/PatternTokenizerFactory.java +++ b/src/java/org/apache/solr/analysis/PatternTokenizerFactory.java @@ -39,18 +39,18 @@ import java.util.regex.Pattern; * "pattern" is the regular expression. * "group" says which group to extract into tokens. * - * group=-1 (the default) is equuivolent to "split". In this case, the tokes will - * be equivolent to the output from: + * group=-1 (the default) is equivalent to "split". In this case, the tokens will + * be equivalent to the output from: * * http://java.sun.com/j2se/1.4.2/docs/api/java/lang/String.html#split(java.lang.String) * - * Using group >= 0 selects the matching group as the token. For example, it you have: + * Using group >= 0 selects the matching group as the token. For example, if you have: * * pattern = \'([^\']+)\' * group = 0 * input = aaa 'bbb' 'ccc' * - * the output will be two tokens: 'bbb' and 'ccc' (including the ' marks). With the same input + * the output will be two tokens: 'bbb' and 'ccc' (including the ' marks). With the same input * but using group=1, the output would be: bbb and ccc (no ' marks) * *