Use actual hostname instead of example.com in subdirectory/subdomain examples. fixes #12679, props johnbillion.
git-svn-id: http://svn.automattic.com/wordpress/trunk@13811 1a063a9b-81f0-0310-95a4-ce76da25c4cd
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@ -139,11 +139,11 @@ function network_step1( $errors = false ) {
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<table class="form-table">
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<tr>
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<th><label><input type='radio' name='subdomain_install' value='1'<?php checked( $subdomain_install ); ?> /> Sub-domains</label></th>
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<td><?php _e('like <code>site1.example.com</code> and <code>site2.example.com</code>'); ?></td>
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<td><?php printf( _x( 'like <code>site1.%1$s</code> and <code>site2.%1$s</code>', 'subdomain examples' ), $hostname ); ?></td>
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</tr>
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<tr>
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<th><label><input type='radio' name='subdomain_install' value='0'<?php checked( ! $subdomain_install ); ?> /> Sub-directories</label></th>
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<td><?php _e('like <code>example.com/site1</code> and <code>example.com/site2</code>'); ?></td>
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<td><?php printf( _x( 'like <code>%1$s/site1</code> and <code>%1$s/site2</code>', 'subdirectory examples' ), $hostname ); ?></td>
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</tr>
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</table>
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