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SQL: [Tests] Add integ tests for selecting a literal and an aggregate (#42121) 

The related issue regarding aggregation queries where some literals
are also selected together with aggregate function has been fixed
with #49570. Add integration tests to verify the behavior.

Relates to: #41411

(cherry picked from commit 9f414a8d05c75e1a9f8250084f6dcd634d5d78d8)
This commit is contained in:
Emanuele Sabellico 2020-02-07 18:26:12 +01:00 committed by Marios Trivyzas
parent 7c6264b28c
commit 282e919607
1 changed files with 45 additions and 3 deletions
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48
x-pack/plugin/sql/qa/src/main/resources/agg.sql-spec
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@ -348,7 +348,7 @@ SELECT gender g, MAX(emp_no) m FROM "test_emp" GROUP BY g HAVING MAX(emp_no) > 1
aggMaxWithHavingOnAlias
SELECT gender g, MAX(emp_no) m FROM "test_emp" GROUP BY g HAVING m > 10 ORDER BY g ;
aggMaxWithMultipleHaving
SELECT gender g, MAX(emp_no) m FROM "test_emp" GROUP BY g HAVING m > 10 AND m < 99999 ORDER BY gender;
SELECT gender g, MAX(emp_no) m FROM "test_emp" GROUP BY g HAVING m > 10 AND m < 99999 ORDER BY gender;
aggMaxWithMultipleHavingBetween
SELECT gender g, MAX(emp_no) m FROM "test_emp" GROUP BY g HAVING m BETWEEN 10 AND 99999 ORDER BY g ;
aggMaxWithMultipleHavingWithLimit
@ -435,7 +435,7 @@ SELECT 1 FROM test_emp HAVING COUNT(*) > 0;
implicitGroupingWithLiteralAliasAndFiltering
SELECT 1 AS l FROM test_emp HAVING COUNT(*) > 0;
implicitGroupingWithLiteralAndFilteringOnAlias
SELECT 1, COUNT(*) AS c FROM test_emp HAVING c > 0;
SELECT 1, COUNT(*) AS c FROM test_emp HAVING c > 0;
implicitGroupingWithLiteralAliasAndFilteringOnAlias
SELECT 1 AS l FROM test_emp HAVING COUNT(*) > 0;
implicitGroupingWithAggs
@ -497,7 +497,7 @@ SELECT MIN(salary) mi, MAX(salary) ma, MAX(salary) - MIN(salary) AS d FROM test_
//
// Mixture of aggs that get promoted plus filtering on one of them
// Mixture of aggs that get promoted plus filtering on one of them
//
aggMultiWithHaving
SELECT MIN(salary) min, MAX(salary) max, gender g, COUNT(*) c FROM "test_emp" WHERE languages > 0 GROUP BY g HAVING max > 74600 ORDER BY gender;
@ -565,3 +565,45 @@ implicitGroupByWithLiteral
SELECT 10, MAX("salary") FROM test_emp;
groupByWithLiteralAndCount
SELECT 20, COUNT(*) from test_emp GROUP BY gender ORDER BY 2;
groupByNumberWithLiteral
SELECT emp_no e, 5 FROM "test_emp" GROUP BY emp_no ORDER BY e DESC;
groupByNumberWithWhereWithLiteral
SELECT emp_no e, 5 FROM "test_emp" WHERE emp_no < 10020 GROUP BY e ORDER BY emp_no DESC;
groupByMulScalarWithLiterals
SELECT emp_no * 2 AS e , 5, TRUE FROM test_emp GROUP BY e ORDER BY e;
groupByMulScalarWithWhereWithLiterals
SELECT emp_no * 2 AS e, 5, TRUE FROM test_emp WHERE emp_no < 10020 GROUP BY e ORDER BY e;
aggMaxImplicitWithLiteral
SELECT MAX(salary) AS max, 5 FROM test_emp;
aggMaxImplicitWithCastWithLiteral
SELECT CAST(MAX(emp_no) AS SMALLINT) c, 5 FROM "test_emp";
aggMaxImplicitWithCastWithWhereWithLiteral
SELECT CAST(MAX(emp_no) AS SMALLINT) c, 5 FROM "test_emp" WHERE emp_no > 10000;
aggSumWithCastWithLiteral
SELECT gender g, CAST(SUM(emp_no) AS BIGINT) s, TRUE FROM "test_emp" GROUP BY gender ORDER BY gender;
aggSumWithCastWithAliasWithLiteral
SELECT TRUE, gender g, CAST(SUM(emp_no) AS BIGINT) s FROM "test_emp" GROUP BY g ORDER BY g DESC;
aggSumWithWhereWithLiteral
SELECT TRUE, gender g, CAST(SUM(emp_no) AS BIGINT) s FROM "test_emp" WHERE emp_no > 10000 GROUP BY gender ORDER BY gender;
// group by with aliased literal
groupByNumberWithLiteralWithAlias
SELECT emp_no e, 5 department FROM "test_emp" GROUP BY emp_no ORDER BY e DESC;
groupByNumberWithWhereWithLiteralWithAlias
SELECT emp_no e, 5 department FROM "test_emp" WHERE emp_no < 10020 GROUP BY e ORDER BY emp_no DESC;
groupByMulScalarWithLiteralsWithAliases
SELECT emp_no * 2 AS e, 5 department, TRUE as employed FROM test_emp GROUP BY e ORDER BY e;
groupByMulScalarWithWhereWithLiteralsWithAliases
SELECT emp_no * 2 AS e, 5 department, TRUE as employed FROM test_emp WHERE emp_no < 10020 GROUP BY e ORDER BY e;
aggMaxImplicitWithLiteralWithAlias
SELECT MAX(salary) AS max, 5 department FROM test_emp;
aggMaxImplicitWithCastWithLiteralWithAlias
SELECT CAST(MAX(emp_no) AS SMALLINT) c, 5 department FROM "test_emp";
aggMaxImplicitWithCastWithWhereWithLiteralWithAlias
SELECT CAST(MAX(emp_no) AS SMALLINT) c, 5 department FROM "test_emp" WHERE emp_no > 10000;
aggSumWithCastWithLiteralWithAlias
SELECT gender g, CAST(SUM(emp_no) AS BIGINT) s, TRUE as employed FROM "test_emp" GROUP BY gender ORDER BY gender;
aggSumWithCastWithAliasWithLiteralWithAlias
SELECT TRUE as employed, gender g, CAST(SUM(emp_no) AS BIGINT) s FROM "test_emp" GROUP BY g ORDER BY g DESC;
aggSumWithWhereWithLiteralWithAlias
SELECT TRUE as employed, gender g, CAST(SUM(emp_no) AS BIGINT) s FROM "test_emp" WHERE emp_no > 10000 GROUP BY gender ORDER BY gender;