SELECT state, COUNT(*) for clarity
Adding state to the SQL syntax to make it more clear, given that the buckets returned include the values of state AND count for each. Closes #13597
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@ -915,7 +915,7 @@ In SQL, the above aggregation is similar in concept to:
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[source,sh]
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SELECT COUNT(*) from bank GROUP BY state ORDER BY COUNT(*) DESC
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SELECT state, COUNT(*) FROM bank GROUP BY state ORDER BY COUNT(*) DESC
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--------------------------------------------------
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And the response (partially shown):
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