SQL: Fix incorrect HAVING equality (#31820)

Fix bug that causes `HAVING a = b` to be translated ad-litteram in
Painless which uses `==` for equality checks not `=`.

Close #31796
This commit is contained in:
Costin Leau 2018-07-06 12:46:57 +03:00 committed by GitHub
parent cce7dc20ad
commit 89cb0872cf
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3 changed files with 8 additions and 2 deletions

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@ -27,6 +27,7 @@ public class Equals extends BinaryComparison {
return new Equals(location(), newLeft, newRight);
}
@Override
public Object fold() {
return Objects.equals(left().fold(), right().fold());
}
@ -38,6 +39,6 @@ public class Equals extends BinaryComparison {
@Override
public String symbol() {
return "=";
return "==";
}
}

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@ -65,7 +65,7 @@ public class CliExplainIT extends CliIntegrationTestCase {
assertThat(readLine(), startsWith("----------"));
assertThat(readLine(), startsWith("With[{}]"));
assertThat(readLine(), startsWith("\\_Project[[?*]]"));
assertThat(readLine(), startsWith(" \\_Filter[?i = 2]"));
assertThat(readLine(), startsWith(" \\_Filter[?i == 2]"));
assertThat(readLine(), startsWith(" \\_UnresolvedRelation[[][index=test],null,Unknown index [test]]"));
assertEquals("", readLine());

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@ -80,6 +80,8 @@ SELECT COUNT(DISTINCT hire_date) AS count FROM test_emp;
// Conditional COUNT
aggCountAndHaving
SELECT gender g, COUNT(*) c FROM "test_emp" GROUP BY g HAVING COUNT(*) > 10 ORDER BY gender;
aggCountAndHavingEquality
SELECT gender g, COUNT(*) c FROM "test_emp" GROUP BY g HAVING COUNT(*) = 10 ORDER BY gender;
aggCountOnColumnAndHaving
SELECT gender g, COUNT(gender) c FROM "test_emp" GROUP BY g HAVING COUNT(gender) > 10 ORDER BY gender;
// NOT supported yet since Having introduces a new agg
@ -91,6 +93,8 @@ aggCountOnColumnAndHavingOnAlias
SELECT gender g, COUNT(gender) c FROM "test_emp" GROUP BY g HAVING c > 10 ORDER BY gender;
aggCountOnColumnAndMultipleHaving
SELECT gender g, COUNT(gender) c FROM "test_emp" GROUP BY g HAVING c > 10 AND c < 70 ORDER BY gender ;
aggCountOnColumnAndMultipleHavingEquals
SELECT gender g, COUNT(gender) c FROM "test_emp" GROUP BY g HAVING c > 10 AND c = 63 ORDER BY gender ;
aggCountOnColumnAndMultipleHavingWithLimit
SELECT gender g, COUNT(gender) c FROM "test_emp" GROUP BY g HAVING c > 10 AND c < 70 ORDER BY gender LIMIT 1;
aggCountOnColumnAndHavingBetween
@ -145,6 +149,7 @@ SELECT gender g, MIN(emp_no) m FROM "test_emp" GROUP BY g HAVING m BETWEEN 10 AN
aggMinWithMultipleHavingOnAliasAndFunction
SELECT gender g, MIN(emp_no) m FROM "test_emp" GROUP BY g HAVING m > 10 AND MIN(emp_no) < 99999 ORDER BY gender;
// MAX
aggMaxImplicit
// tag::max