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Docs: unescape regexes in Pattern Tokenizer docs 

Currently regexes in Pattern Tokenizer docs are escaped (it seems according to Java rules). I think it is better not to escape them because JSON escaping should be automatic in client libraries, and string escaping depends on a client language used. The default pattern is `\W+`, not `\\W+`.

Closes #6615
This commit is contained in:
Mikhail Korobov 2014-06-25 23:18:43 +06:00 committed by Clinton Gormley
parent 6e6f4def5d
commit 955473f475
1 changed files with 14 additions and 5 deletions
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19
docs/reference/analysis/tokenizers/pattern-tokenizer.asciidoc
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@ -7,7 +7,7 @@ via a regular expression. Accepts the following settings:
[cols="<,<",options="header",]
|======================================================================
|Setting |Description
|`pattern` |The regular expression pattern, defaults to `\\W+`.
|`pattern` |The regular expression pattern, defaults to `\W+`.
|`flags` |The regular expression flags.
|`group` |Which group to extract into tokens. Defaults to `-1` (split).
|======================================================================
@ -15,15 +15,24 @@ via a regular expression. Accepts the following settings:
*IMPORTANT*: The regular expression should match the *token separators*,
not the tokens themselves.
*********************************************
Note that you may need to escape `pattern` string literal according to
your client language rules. For example, in many programming languages
a string literal for `\W+` pattern is written as `"\\W+"`.
There is nothing special about `pattern` (you may have to escape other
string literals as well); escaping `pattern` is common just because it
often contains characters that should be escaped.
*********************************************
`group` set to `-1` (the default) is equivalent to "split". Using group
>= 0 selects the matching group as the token. For example, if you have:
------------------------
pattern = \\'([^\']+)\\'
pattern = '([^']+)'
group = 0
input = aaa 'bbb' 'ccc'
------------------------
the output will be two tokens: 'bbb' and 'ccc' (including the ' marks).
With the same input but using group=1, the output would be: bbb and ccc
(no ' marks).
the output will be two tokens: `'bbb'` and `'ccc'` (including the `'`
marks). With the same input but using group=1, the output would be:
`bbb` and `ccc` (no `'` marks).