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[TEST] Use _uid sort field as tie, so that hits with the same score are sorted in the same way in both search responses.

This commit is contained in:
Martijn van Groningen 2014-05-22 12:09:51 +02:00
parent 60ba9d1e69
commit a717af505a
1 changed files with 8 additions and 0 deletions
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8
src/test/java/org/elasticsearch/search/query/MultiMatchQueryTests.java
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@ -31,6 +31,7 @@ import org.elasticsearch.index.query.QueryBuilders;
import org.elasticsearch.search.SearchHit;
import org.elasticsearch.search.SearchHits;
import org.elasticsearch.search.sort.SortBuilders;
import org.elasticsearch.search.sort.SortOrder;
import org.elasticsearch.test.ElasticsearchIntegrationTest;
import org.junit.Before;
import org.junit.Test;
@ -233,12 +234,19 @@ public class MultiMatchQueryTests extends ElasticsearchIntegrationTest {
}
MultiMatchQueryBuilder multiMatchQueryBuilder = randomizeType(multiMatchQuery(builder.toString(), field));
SearchResponse multiMatchResp = client().prepareSearch("test")
// _uid sort field is a tie, in case hits have the same score,
// the hits will be sorted the same consistently
.addSort("_score", SortOrder.DESC)
.addSort("_uid", SortOrder.ASC)
.setQuery(multiMatchQueryBuilder).get();
MatchQueryBuilder matchQueryBuilder = QueryBuilders.matchQuery(field, builder.toString());
if (getType(multiMatchQueryBuilder) != null) {
matchQueryBuilder.type(MatchQueryBuilder.Type.valueOf(getType(multiMatchQueryBuilder).matchQueryType().toString()));
}
SearchResponse matchResp = client().prepareSearch("test")
// _uid tie sort
.addSort("_score", SortOrder.DESC)
.addSort("_uid", SortOrder.ASC)
.setQuery(matchQueryBuilder).get();
assertThat("field: " + field + " query: " + builder.toString(), multiMatchResp.getHits().getTotalHits(), equalTo(matchResp.getHits().getTotalHits()));
SearchHits hits = multiMatchResp.getHits();