angular-cn/modules/@angular/router/test/tree_spec.ts

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import {
AsyncTestCompleter,
beforeEach,
ddescribe,
xdescribe,
describe,
expect,
iit,
inject,
beforeEachProviders,
it,
xit
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} from '@angular/core/testing/testing_internal';
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import {Tree, TreeNode} from '../src/segments';
export function main() {
describe('tree', () => {
it("should return the root of the tree", () => {
let t = new Tree<any>(new TreeNode<number>(1, []));
expect(t.root).toEqual(1);
});
it("should return the parent of a node", () => {
let t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])]));
expect(t.parent(1)).toEqual(null);
expect(t.parent(2)).toEqual(1);
});
it("should return the children of a node", () => {
let t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])]));
expect(t.children(1)).toEqual([2]);
expect(t.children(2)).toEqual([]);
});
it("should return the first child of a node", () => {
let t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])]));
expect(t.firstChild(1)).toEqual(2);
expect(t.firstChild(2)).toEqual(null);
});
it("should return the path to the root", () => {
let t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])]));
expect(t.pathFromRoot(2)).toEqual([1, 2]);
});
describe("contains", () => {
it("should work", () => {
let tree = new Tree<any>(
new TreeNode<number>(1, [new TreeNode<number>(2, []), new TreeNode<number>(3, [])]));
let subtree1 = new Tree<any>(new TreeNode<number>(1, []));
let subtree2 = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])]));
let subtree3 = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(3, [])]));
let notSubtree1 = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(4, [])]));
let notSubtree2 = new Tree<any>(
new TreeNode<number>(1, [new TreeNode<number>(2, [new TreeNode<number>(4, [])])]));
expect(tree.contains(subtree1)).toEqual(true);
expect(tree.contains(subtree2)).toEqual(true);
expect(tree.contains(subtree3)).toEqual(true);
expect(tree.contains(notSubtree1)).toEqual(false);
expect(tree.contains(notSubtree2)).toEqual(false);
});
});
});
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}