perf(language-service): Skip Angular analysis when quick info requested outside a template (#40956)

The Angular LS does not provide quick info when the given position is not
inside a template. As an optimization, we can quickly look at the
file and determine if we are at a position that is part of an Angular
template. If not, we bail before asking the compiler for any more
information. Note that the Angular LS _already_ provides no quick info
when outside a template file, but currently asks the compiler to analyze
the program before it determines that information.

PR Close #40956
This commit is contained in:
Andrew Scott 2021-02-22 15:29:28 -08:00 committed by atscott
parent 49e02ca7d6
commit ad38cbbe09
1 changed files with 21 additions and 18 deletions

View File

@ -96,7 +96,11 @@ export class LanguageService {
}
getQuickInfoAtPosition(fileName: string, position: number): ts.QuickInfo|undefined {
const compiler = this.compilerFactory.getOrCreate();
return this.withCompiler((compiler) => {
if (!isTemplateContext(compiler.getNextProgram(), fileName, position)) {
return undefined;
}
const templateInfo = getTemplateInfoAtPosition(fileName, position, compiler);
if (templateInfo === undefined) {
return undefined;
@ -112,9 +116,8 @@ export class LanguageService {
const node = positionDetails.context.kind === TargetNodeKind.TwoWayBindingContext ?
positionDetails.context.nodes[0] :
positionDetails.context.node;
const results = new QuickInfoBuilder(this.tsLS, compiler, templateInfo.component, node).get();
this.compilerFactory.registerLastKnownProgram();
return results;
return new QuickInfoBuilder(this.tsLS, compiler, templateInfo.component, node).get();
});
}
getReferencesAtPosition(fileName: string, position: number): ts.ReferenceEntry[]|undefined {