angular-docs-cn/aio/content/guide/migration-module-with-providers.md

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# `ModuleWithProviders` Migration
# `ModuleWithProviders` 迁移
## What does this schematic do?
## 这个原理图做了什么?
Some Angular libraries, such as `@angular/router` and `@ngrx/store`, implement APIs that return a type called `ModuleWithProviders` (typically via a method named `forRoot()`).
This type represents an `NgModule` along with additional providers.
Angular version 9 deprecates use of `ModuleWithProviders` without an explicitly generic type, where the generic type refers to the type of the `NgModule`.
一些 Angular 库,比如 `@angular/router``@ngrx/store`,实现了某些返回 `ModuleWithProviders` 类型的 API通常是一个名叫 `forRoot()` 的方法)。这种类型代表了一个 `NgModule` 以及其提供者。Angular 9 不推荐使用不带泛型的 `ModuleWithProviders`,泛型类型就是 `NgModule` 的类型。
This schematic will add a generic type to any `ModuleWithProviders` usages that are missing the generic.
In the example below, the type of the `NgModule` is `SomeModule`, so the schematic changes the type to be `ModuleWithProviders<SomeModule>`.
这个原理图会给那些缺少泛型的 `ModuleWithProviders` 用法添加泛型类型。在下面的例子中,`NgModule` 的类型是 `SomeModule`,所以原理图就把类型修改为 `ModuleWithProviders<SomeModule>`
**Before**
**以前**
```ts
@NgModule({...})
export class MyModule {
static forRoot(config: SomeConfig): ModuleWithProviders {
return {
ngModule: SomeModule,
providers: [
{provide: SomeConfig, useValue: config}
]
};
}
}
```
**After**
**以后**
```ts
@NgModule({...})
export class MyModule {
static forRoot(config: SomeConfig): ModuleWithProviders<SomeModule> {
return {
ngModule: SomeModule,
providers: [
{provide: SomeConfig, useValue: config }
]
};
}
}
```
In the rare case that the schematic can't determine the type of `ModuleWithProviders`, you may see the schematic print a TODO comment to update the code manually.
在极少数情况下,原理图无法确定 `ModuleWithProviders` 的类型,你可能会看到原理图打印出一条 TODO 注释来让你手动更新代码。
## Why is this migration necessary?
## 为何这项迁移是必要的?
`ModuleWithProviders` has had the generic type since Angular version 7, but it has been optional.
This has compiled because the `metadata.json` files contained all the metadata.
With Ivy, `metadata.json` files are no longer required, so the framework cannot assume that one with the necessary types has been provided.
Instead, Ivy relies on the generic type for `ModuleWithProviders` to get the correct type information.
自 Angular 7 开始,`ModuleWithProviders` 就有了泛型类型,但它是可选的。即使缺了也可以正常编译,因为 `metadata.json` 文件中包含了所有的元数据。在 Ivy 中,不再需要 `metadata.json` 文件了所以框架不能再假定已经有了所有必要的类型。相反Ivy 要依赖 `ModuleWithProviders` 的泛型类型来获取正确的类型信息。
For this reason, Angular version 9 deprecates `ModuleWithProviders` without a generic type.
A future version of Angular will remove the default generic type, making an explicit type required.
出于这个原因Angular 9 版本不推荐使用不带泛型类型的 `ModuleWithProviders`。Angular 的未来版本会删除默认的泛型类型,并且要求一个明确的类型。
## Should I add the generic type when I add new `ModuleWithProviders` types to my application?
## 当我把新的 `ModuleWithProviders` 类型添加到应用中时,是否应该添加泛型?
Yes, any time your code references the `ModuleWithProviders` type, it should have a generic type that matches the actual `NgModule` that is returned (for example, `ModuleWithProviders<MyModule>`).
是的,任何时候,当你的代码引用了 `ModuleWithProviders` 类型,都要有一个与其返回的实际 `NgModule` 相匹配的泛型类型(例如,`ModuleWithProviders<MyModule>` )。
## What should I do if the schematic prints a TODO comment?
## 如果此原理图打印出了 TODO 注释,我该怎么办?
The schematic will print a TODO comment in the event that it cannot detect the correct generic for the `ModuleWithProviders` type.
In this case, you'll want to manually add the correct generic to `ModuleWithProviders`. It should match the type of whichever `NgModule` is returned in the `ModuleWithProviders` object.
此原理图会在它无法检测出 `ModuleWithProviders` 类型的正确泛型类型的情况下打印 TODO 注释。在这种情况下,你需要手动为 `ModuleWithProviders` 添加正确的泛型。它应该匹配 `ModuleWithProviders` 对象中返回的那个 `NgModule`
## What does this mean for libraries?
## 这对库意味着什么?
Libraries should add the generic type to any usages of the `ModuleWithProviders` type.
库应该把泛型类型添加到 `ModuleWithProviders` 类型的任何一次使用中。
## What about applications using non-migrated libraries?
## 那些使用未迁移库的应用呢?
The [Angular compatibility compiler](guide/glossary#ngcc) (`ngcc`) should automatically transform any non-migrated libraries to generate the proper code.
[Angular 兼容性编译器](guide/glossary#ngcc) `ngcc` )会自动转换所有未迁移的库来生成合适的代码。