angular-docs-cn/packages/router/test/utils/tree.spec.ts

54 lines
1.9 KiB
TypeScript

/**
* @license
* Copyright Google LLC All Rights Reserved.
*
* Use of this source code is governed by an MIT-style license that can be
* found in the LICENSE file at https://angular.io/license
*/
import {Tree, TreeNode} from '../../src/utils/tree';
describe('tree', () => {
it('should return the root of the tree', () => {
const t = new Tree<any>(new TreeNode<number>(1, [])) as any;
expect(t.root).toEqual(1);
});
it('should return the parent of a node', () => {
const t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])])) as any;
expect(t.parent(1)).toEqual(null);
expect(t.parent(2)).toEqual(1);
});
it('should return the parent of a node (second child)', () => {
const t = new Tree<any>(new TreeNode<number>(
1, [new TreeNode<number>(2, []), new TreeNode<number>(3, [])])) as any;
expect(t.parent(1)).toEqual(null);
expect(t.parent(3)).toEqual(1);
});
it('should return the children of a node', () => {
const t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])])) as any;
expect(t.children(1)).toEqual([2]);
expect(t.children(2)).toEqual([]);
});
it('should return the first child of a node', () => {
const t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])])) as any;
expect(t.firstChild(1)).toEqual(2);
expect(t.firstChild(2)).toEqual(null);
});
it('should return the siblings of a node', () => {
const t = new Tree<any>(new TreeNode<number>(
1, [new TreeNode<number>(2, []), new TreeNode<number>(3, [])])) as any;
expect(t.siblings(2)).toEqual([3]);
expect(t.siblings(1)).toEqual([]);
});
it('should return the path to the root', () => {
const t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])])) as any;
expect(t.pathFromRoot(2)).toEqual([1, 2]);
});
});