angular-docs-cn/modules/@angular/router/test/utils/tree.spec.ts

66 lines
2.5 KiB
TypeScript

/**
* @license
* Copyright Google Inc. All Rights Reserved.
*
* Use of this source code is governed by an MIT-style license that can be
* found in the LICENSE file at https://angular.io/license
*/
import {Tree, TreeNode} from '../../src/utils/tree';
describe('tree', () => {
it('should return the root of the tree', () => {
const t = new Tree<any>(new TreeNode<number>(1, []));
expect(t.root).toEqual(1);
});
it('should return the parent of a node', () => {
const t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])]));
expect(t.parent(1)).toEqual(null);
expect(t.parent(2)).toEqual(1);
});
it('should return the children of a node', () => {
const t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])]));
expect(t.children(1)).toEqual([2]);
expect(t.children(2)).toEqual([]);
});
it('should return the first child of a node', () => {
const t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])]));
expect(t.firstChild(1)).toEqual(2);
expect(t.firstChild(2)).toEqual(null);
});
it('should return the siblings of a node', () => {
const t = new Tree<any>(
new TreeNode<number>(1, [new TreeNode<number>(2, []), new TreeNode<number>(3, [])]));
expect(t.siblings(2)).toEqual([3]);
expect(t.siblings(1)).toEqual([]);
});
it('should return the path to the root', () => {
const t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])]));
expect(t.pathFromRoot(2)).toEqual([1, 2]);
});
describe('contains', () => {
it('should work', () => {
const tree = new Tree<any>(
new TreeNode<number>(1, [new TreeNode<number>(2, []), new TreeNode<number>(3, [])]));
const subtree1 = new Tree<any>(new TreeNode<number>(1, []));
const subtree2 = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])]));
const subtree3 = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(3, [])]));
const notSubtree1 = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(4, [])]));
const notSubtree2 = new Tree<any>(
new TreeNode<number>(1, [new TreeNode<number>(2, [new TreeNode<number>(4, [])])]));
expect(tree.contains(subtree1)).toEqual(true);
expect(tree.contains(subtree2)).toEqual(true);
expect(tree.contains(subtree3)).toEqual(true);
expect(tree.contains(notSubtree1)).toEqual(false);
expect(tree.contains(notSubtree2)).toEqual(false);
});
});
});