LintCode 0425 题目,采用递归实现
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package com.ossez.lang.tutorial.tests.lintcode;
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import java.util.ArrayList;
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import java.util.HashMap;
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import java.util.List;
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import org.junit.Test;
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import org.slf4j.Logger;
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import org.slf4j.LoggerFactory;
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/**
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* <p>
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* 425
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* <ul>
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* <li>@see <a href="https://www.cwiki.us/display/ITCLASSIFICATION/Gray+Code">https://www.cwiki.us/display/ITCLASSIFICATION/Gray+Code</a>
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* <li>@see<a href=
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* "https://www.lintcode.com/problem/letter-combinations-of-a-phone-number/description">https://www.lintcode.com/problem/letter-combinations-of-a-phone-number/description</a>
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* </ul>
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* </p>
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*
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* @author YuCheng
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*
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*/
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public class LintCode0425LetterCombinationsTest {
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private final static Logger logger = LoggerFactory.getLogger(LintCode0425LetterCombinationsTest.class);
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/**
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*
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*/
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@Test
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public void testMain() {
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logger.debug("LetterCombinationsTest");
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String digits = "23";
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HashMap<String, String> phoneKeyMap = new HashMap<String, String>();
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phoneKeyMap.put("0", "");
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phoneKeyMap.put("1", "");
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phoneKeyMap.put("2", "abc");
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phoneKeyMap.put("3", "def");
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phoneKeyMap.put("4", "ghi");
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phoneKeyMap.put("5", "jkl");
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phoneKeyMap.put("6", "mno");
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phoneKeyMap.put("7", "pqrs");
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phoneKeyMap.put("8", "tuv");
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phoneKeyMap.put("9", "wxyz");
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List<String> retStatus = new ArrayList<>();
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if (digits != null && digits.length() != 0) {
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phoneRecursive(digits, retStatus, phoneKeyMap, "", 0);
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}
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System.out.println(retStatus);
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}
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/**
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* phoneRecursive
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*
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* @param digits
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* @param retStatus
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* @param phoneKeyMap
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* @param comb
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* @param index
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*/
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private void phoneRecursive(String digits, List<String> retStatus, HashMap<String, String> phoneKeyMap, String comb, int index) {
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if (index == digits.length()) {
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retStatus.add(comb);
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return;
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}
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char pos = digits.charAt(index);
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for (char c : ((String) phoneKeyMap.get(String.valueOf(pos))).toCharArray()) {
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phoneRecursive(digits, retStatus, phoneKeyMap, comb + c, index + 1);
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}
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}
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}
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