[scanner-with-spaces] how to take input as String with spaces in Java… (#14044)

* [scanner-with-spaces] how to take input as String with spaces in Java using Scanner?y

* [scanner-with-spaces] fix typo

core-java-modules/core-java-io-apis-2/src/test/java/com/baeldung/scanner/InputWithSpacesUnitTest.java

@@ -0,0 +1,97 @@
+package com.baeldung.scanner;
+
+import static org.junit.jupiter.api.Assertions.assertArrayEquals;
+import static org.junit.jupiter.api.Assertions.assertEquals;
+
+import java.util.ArrayList;
+import java.util.List;
+import java.util.Scanner;
+
+import org.junit.jupiter.api.Test;
+
+import com.google.common.collect.Lists;
+
+public class InputWithSpacesUnitTest {
+    @Test
+    void whenValuesContainSpaces_thenNextBreaksTheValue() {
+        String input = new StringBuilder().append("Michael Jackson\n")
+          .append("He was the 'King of Pop'.\n")
+          .toString();
+
+        Scanner sc = new Scanner(input);
+        String name = sc.next();
+        String description = sc.next();
+        assertEquals("Michael", name);
+        assertEquals("Jackson", description);
+    }
+
+    @Test
+    void whenOneValuePerLineUsingNextLine_thenGetExpectedResult() {
+        String input = new StringBuilder().append("Michael Jackson\n")
+          .append("He was the 'King of Pop'.\n")
+          .toString();
+
+        Scanner sc = new Scanner(input);
+        String name = sc.nextLine();
+        String description = sc.nextLine();
+        assertEquals("Michael Jackson", name);
+        assertEquals("He was the 'King of Pop'.", description);
+    }
+
+    @Test
+    void whenOneValuePerLineUsingNewLineAsDelimiter_thenGetExpectedResult() {
+        String input = new StringBuilder().append("Michael Jackson\n")
+          .append("He was the 'King of Pop'.\n")
+          .toString();
+
+        Scanner sc = new Scanner(input);
+        sc.useDelimiter("\\n");
+        String name = sc.next();
+        String description = sc.next();
+        assertEquals("Michael Jackson", name);
+        assertEquals("He was the 'King of Pop'.", description);
+    }
+
+    @Test
+    void whenValuesAreSeparatedByCommaUsingSplit_thenGetExpectedResult() {
+        String input = "Michael Jackson, Whitney Houston, John Lennon\n";
+
+        Scanner sc = new Scanner(input);
+        String[] names = sc.nextLine()
+          .split(", ");
+        assertArrayEquals(new String[] { "Michael Jackson", "Whitney Houston", "John Lennon" }, names);
+    }
+
+    @Test
+    void whenValuesAreSeparatedByCommaSettingDelimiterWithoutNewline_thenGetExpectedResult() {
+        String input = new StringBuilder().append("Michael Jackson, Whitney Houston, John Lennon\n")
+          .append("Elvis Presley\n")
+          .toString();
+
+        Scanner sc = new Scanner(input);
+        sc.useDelimiter(", ");
+        List<String> names = new ArrayList<>();
+        while (sc.hasNext()) {
+            names.add(sc.next());
+        }
+        //assertEquals(Lists.newArrayList("Michael Jackson", "Whitney Houston", "John Lennon", "Elvis Presley"), names); <-- Fail
+        assertEquals(3, names.size());
+        assertEquals("John Lennon\nElvis Presley\n", names.get(2));
+
+    }
+
+    @Test
+    void whenValuesAreSeparatedByCommaSettingDelimiter_thenGetExpectedResult() {
+        String input = new StringBuilder().append("Michael Jackson, Whitney Houston, John Lennon\n")
+          .append("Elvis Presley\n")
+          .toString();
+
+        Scanner sc = new Scanner(input);
+        sc.useDelimiter(", |\\n");
+        List<String> names = new ArrayList<>();
+        while (sc.hasNext()) {
+            names.add(sc.next());
+        }
+        assertEquals(Lists.newArrayList("Michael Jackson", "Whitney Houston", "John Lennon", "Elvis Presley"), names);
+    }
+}