Removing my helper script

scripts/linuxcompile.sh

@@ -1,60 +0,0 @@
-#!/bin/bash
-#
-# To be able to cross compile:
-#   cd /usr/local/go/src
-#   sudo GOOS=linux GOARCH=amd64 ./make.bash --no-clean
-#
-# This script only builds the application from source.
-set -e
-
-NO_COLOR="\x1b[0m"
-OK_COLOR="\x1b[32;01m"
-ERROR_COLOR="\x1b[31;01m"
-WARN_COLOR="\x1b[33;01m"
-
-# http://stackoverflow.com/questions/4023830/bash-how-compare-two-strings-in-version-format
-verify_go () {
-    if [[ $1 == $2 ]]; then
-        return 0
-    fi
-
-    local IFS=.
-    local i ver1=($1) ver2=($2)
-
-    for ((i=${#ver1[@]}; i<${#ver2[@]}; i++)); do
-        ver1[i]=0
-    done
-
-    for ((i=0; i<${#ver1[@]}; i++)); do
-        if [[ -z ${ver2[i]} ]]; then
-            ver2[i]=0
-        fi
-        if ((10#${ver1[i]} > 10#${ver2[i]})); then
-            echo -e "${ERROR_COLOR}==> Required Go version $1 not installed. Found $2 instead"
-            exit 1
-        fi
-    done
-}
-
-GO_MINIMUM_VERSION=1.2
-GO_INSTALLED_VERSION=$(go version | cut -d ' ' -f 3)
-GO_INSTALLED_VERSION=${GO_INSTALLED_VERSION#"go"}
-
-echo -e "${OK_COLOR}==> Verifying Go"
-verify_go $GO_MINIMUM_VERSION $GO_INSTALLED_VERSION
-
-# Get the parent directory of where this script is.
-SOURCE="${BASH_SOURCE[0]}"
-while [ -h "$SOURCE" ] ; do SOURCE="$(readlink "$SOURCE")"; done
-DIR="$( cd -P "$( dirname "$SOURCE" )/.." && pwd )"
-
-# Change into that directory
-cd $DIR
-
-# Compile the thing
-export XC_ARCH=amd64
-export XC_OS=linux
-./scripts/compile.sh
-
-echo "-- DONE --"
-echo "Binaries are in ./pkg/linux_amd64/"