42 lines
2.3 KiB
Mathematica
42 lines
2.3 KiB
Mathematica
HLFNC3 ;AISC/SAW-Continuation of HLFNC, Additional Functions/Calls Used for HL7 Messages ;1/17/95 11:16
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;;1.6;HEALTH LEVEL SEVEN;;Oct 13, 1995
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BHS(HL,BID,RESULT,SECURITY,MSA) ;Create a BHS Segment for an Outgoing HL7
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;Batch Message
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;
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;This is a subroutine call with parameter passing that returns an HL7
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;Batch Header (BHS) segment in the variable RESULT (and possibly
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;RESULT(1) if the BHS segment is longer than 245 characters). If the
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;required input parameters HL or BID are missing, RESULT is returned
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;equal to null
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;
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;Required Input Parameters
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; HL = The array of values returned by the call to INIT^HLFNC2
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; BID = The Batch Control ID to be included in the BHS segment.
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; The Batch Control ID for the batch is returned by the
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; call to CREATE^HLTF.
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; RESULT = The variable that will be returned to the calling
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; application as described above
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;Optional Input Parameters
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;SECURITY = Security to be included in field #8 of the BHS segment
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; MSA = Three components (separated by the HL7 component separator
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; character) consisting of the first three fields in the
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; MSA segment. This variable is required if the message
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; you are building is a batch acknowledgment
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;
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;Check for required parameters
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I '$D(HL)#2!('$D(BID)) Q ""
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N X,X1,X2
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;Build BHS segment from HL array variables and other input parameters
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S X="BHS"_HL("FS")_HL("ECH")_HL("FS")_HL("SAN")_HL("FS")_HL("SAF")_HL("FS")_$S($D(HL("RAN")):HL("RAN"),1:"")_HL("FS")_$S($D(HL("RAF")):HL("RAF"),1:"")_HL("FS")_$S($D(HL("DTM")):HL("DTM"),1:"")_HL("FS")
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S X=X_$S($G(SECURITY)]"":SECURITY,1:"")_HL("FS")_$E(HL("ECH"))_HL("PID")_$E(HL("ECH"))_HL("MTN")_$E(HL("ECH"))_HL("VER")_HL("FS")_HL("FS")_BID
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;If the MSA parameter exists, insert it in pieces 11 and 12 and
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;create new variable X1 if length of X will be greater than 245
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I $D(MSA) D
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.S $P(X,HL("FS"),12)=$P(MSA,$E(HL("ECH")),2),MSA=$P(MSA,$E(HL("ECH")))_$E(HL("ECH"))_$P(MSA,$E(HL("ECH")),3)
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.I $L(X)+$L(MSA)'>245 S $P(X,HL("FS"),10)=MSA Q
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.S X1=HL("FS")_$P(X,HL("FS"),11,12),X=$P(X,HL("FS"),1,10)
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.S X2=$L(X),X=X_$E(MSA,1,(245-X2)),X1=$E(MSA,(246-X2),245)_X1
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.S X2=$L(X) I $L(X2)<245 S X=X_$E(X1,1,(245-X2)),X1=$E(X1,(246-X2),245)
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S RESULT=X S:$L($G(X1)) RESULT(1)=X1
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Q
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