From 2ca9a1402a241b721225f6effad003bce4f496fd Mon Sep 17 00:00:00 2001
From: Guido van Rossum <guido@python.org>
Date: Thu, 2 Aug 2007 16:51:59 +0000
Subject: [PATCH] Mention that type.__prepare__() exists for use via super().

---
 pep-3115.txt | 4 ++++
 1 file changed, 4 insertions(+)

diff --git a/pep-3115.txt b/pep-3115.txt
index fefb074d9..d6fd7a130 100644
--- a/pep-3115.txt
+++ b/pep-3115.txt
@@ -132,6 +132,10 @@ Invoking the Metaclass
      assignment algorithm. (Note also that 'metaclass' is a keyword-
      only argument as per PEP 3102 [6].)
 
+     Even though __prepare__ is not required, the default metaclass
+     ('type') implements it, for the convenience of subclasses calling
+     it via super().
+
      __prepare__ returns a dictionary-like object which is used to store
      the class member definitions during evaluation of the class body.
      In other words, the class body is evaluated as a function block