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Fixes PEP 505 grammar (#699)

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Steve Dower 2018-07-08 15:55:45 -07:00 committed by GitHub
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pep-0505.rst
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@ -62,10 +62,9 @@ The following rules of the Python grammar are updated to read::
augassign: ('+=' | '-=' | '*=' | '@=' | '/=' | '%=' | '&=' | '|=' | '^=' | augassign: ('+=' | '-=' | '*=' | '@=' | '/=' | '%=' | '&=' | '|=' | '^=' |
'<<=' | '>>=' | '**=' | '//=' | '??=') '<<=' | '>>=' | '**=' | '//=' | '??=')
term: coalesce (('*'|'@'|'/'|'%'|'//') coalesce)*
coalesce: factor ('??' factor)*
# factor eventually resolved to atom_expr power: coalesce ['**' factor]
coalesce: atom_expr ['??' factor]
atom_expr: ['await'] atom trailer* atom_expr: ['await'] atom trailer*
trailer: ('(' [arglist] ')' | trailer: ('(' [arglist] ')' |
'[' subscriptlist ']' | '[' subscriptlist ']' |
@ -83,8 +82,8 @@ determined to be ``None``. For example::
def c(): return None def c(): return None
def ex(): raise Exception() def ex(): raise Exception()
(a ?? 2 ** b ?? 3) == a ?? (2 ** b) ?? 3 (a ?? 2 ** b ?? 3) == a ?? (2 ** (b ?? 3))
(a * b ?? c // d) == (a * b) ?? (c // d) (a * b ?? c // d) == a * (b ?? c) // d
(a ?? True and b ?? False) == (a ?? True) and (b ?? False) (a ?? True and b ?? False) == (a ?? True) and (b ?? False)
(c() ?? c() ?? True) == True (c() ?? c() ?? True) == True
(True ?? ex()) == True (True ?? ex()) == True