discourse/spec/lib/gaps_spec.rb

Ignoring revisions in .git-blame-ignore-revs. Click here to bypass and see the normal blame view.

79 lines
1.9 KiB
Ruby
Raw Normal View History

# frozen_string_literal: true
require "cache"
RSpec.describe Gaps do
it "returns no gaps for empty data" do
2015-01-09 11:34:37 -05:00
expect(Gaps.new(nil, nil)).to be_blank
end
it "returns no gaps with one element" do
2015-01-09 11:34:37 -05:00
expect(Gaps.new([1], [1])).to be_blank
end
it "returns no gaps when all elements are present" do
2015-01-09 11:34:37 -05:00
expect(Gaps.new([1, 2, 3], [1, 2, 3])).to be_blank
end
describe "single element gap" do
let(:gap) { Gaps.new([1, 3], [1, 2, 3]) }
it "has a gap for post 3" do
2015-01-09 11:34:37 -05:00
expect(gap).not_to be_blank
expect(gap.before[3]).to eq([2])
expect(gap.after).to be_blank
end
end
describe "larger gap" do
let(:gap) { Gaps.new([1, 2, 3, 6, 7], [1, 2, 3, 4, 5, 6, 7]) }
it "has a gap for post 6" do
2015-01-09 11:34:37 -05:00
expect(gap).not_to be_blank
expect(gap.before[6]).to eq([4, 5])
expect(gap.after).to be_blank
end
end
describe "multiple gaps" do
let(:gap) { Gaps.new([1, 5, 6, 7, 10], [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) }
it "has both gaps" do
2015-01-09 11:34:37 -05:00
expect(gap).not_to be_blank
expect(gap.before[5]).to eq([2, 3, 4])
expect(gap.before[10]).to eq([8, 9])
expect(gap.after).to be_blank
end
end
describe "a gap in the beginning" do
let(:gap) { Gaps.new([2, 3, 4], [1, 2, 3, 4]) }
it "has the gap" do
2015-01-09 11:34:37 -05:00
expect(gap).not_to be_blank
expect(gap.before[2]).to eq([1])
expect(gap.after).to be_blank
end
end
describe "a gap in the ending" do
let(:gap) { Gaps.new([1, 2, 3], [1, 2, 3, 4]) }
it "has the gap" do
2015-01-09 11:34:37 -05:00
expect(gap).not_to be_blank
expect(gap.before).to be_blank
expect(gap.after[3]).to eq([4])
end
end
describe "a large gap in the ending" do
let(:gap) { Gaps.new([1, 2, 3], [1, 2, 3, 4, 5, 6]) }
it "has the gap" do
2015-01-09 11:34:37 -05:00
expect(gap).not_to be_blank
expect(gap.before).to be_blank
expect(gap.after[3]).to eq([4, 5, 6])
end
end
end